3.1569 \(\int \frac {(a+\frac {b}{x})^2}{x^5} \, dx\)

Optimal. Leaf size=30 \[ -\frac {a^2}{4 x^4}-\frac {2 a b}{5 x^5}-\frac {b^2}{6 x^6} \]

[Out]

-1/6*b^2/x^6-2/5*a*b/x^5-1/4*a^2/x^4

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Rubi [A]  time = 0.01, antiderivative size = 30, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.154, Rules used = {263, 43} \[ -\frac {a^2}{4 x^4}-\frac {2 a b}{5 x^5}-\frac {b^2}{6 x^6} \]

Antiderivative was successfully verified.

[In]

Int[(a + b/x)^2/x^5,x]

[Out]

-b^2/(6*x^6) - (2*a*b)/(5*x^5) - a^2/(4*x^4)

Rule 43

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rule 263

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Int[x^(m + n*p)*(b + a/x^n)^p, x] /; FreeQ[{a, b, m
, n}, x] && IntegerQ[p] && NegQ[n]

Rubi steps

\begin {align*} \int \frac {\left (a+\frac {b}{x}\right )^2}{x^5} \, dx &=\int \frac {(b+a x)^2}{x^7} \, dx\\ &=\int \left (\frac {b^2}{x^7}+\frac {2 a b}{x^6}+\frac {a^2}{x^5}\right ) \, dx\\ &=-\frac {b^2}{6 x^6}-\frac {2 a b}{5 x^5}-\frac {a^2}{4 x^4}\\ \end {align*}

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Mathematica [A]  time = 0.00, size = 30, normalized size = 1.00 \[ -\frac {a^2}{4 x^4}-\frac {2 a b}{5 x^5}-\frac {b^2}{6 x^6} \]

Antiderivative was successfully verified.

[In]

Integrate[(a + b/x)^2/x^5,x]

[Out]

-1/6*b^2/x^6 - (2*a*b)/(5*x^5) - a^2/(4*x^4)

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fricas [A]  time = 0.89, size = 24, normalized size = 0.80 \[ -\frac {15 \, a^{2} x^{2} + 24 \, a b x + 10 \, b^{2}}{60 \, x^{6}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b/x)^2/x^5,x, algorithm="fricas")

[Out]

-1/60*(15*a^2*x^2 + 24*a*b*x + 10*b^2)/x^6

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giac [A]  time = 0.15, size = 24, normalized size = 0.80 \[ -\frac {15 \, a^{2} x^{2} + 24 \, a b x + 10 \, b^{2}}{60 \, x^{6}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b/x)^2/x^5,x, algorithm="giac")

[Out]

-1/60*(15*a^2*x^2 + 24*a*b*x + 10*b^2)/x^6

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maple [A]  time = 0.00, size = 25, normalized size = 0.83 \[ -\frac {a^{2}}{4 x^{4}}-\frac {2 a b}{5 x^{5}}-\frac {b^{2}}{6 x^{6}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a+b/x)^2/x^5,x)

[Out]

-1/6*b^2/x^6-2/5*a*b/x^5-1/4*a^2/x^4

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maxima [A]  time = 0.96, size = 24, normalized size = 0.80 \[ -\frac {15 \, a^{2} x^{2} + 24 \, a b x + 10 \, b^{2}}{60 \, x^{6}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b/x)^2/x^5,x, algorithm="maxima")

[Out]

-1/60*(15*a^2*x^2 + 24*a*b*x + 10*b^2)/x^6

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mupad [B]  time = 0.04, size = 24, normalized size = 0.80 \[ -\frac {\frac {a^2\,x^2}{4}+\frac {2\,a\,b\,x}{5}+\frac {b^2}{6}}{x^6} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a + b/x)^2/x^5,x)

[Out]

-(b^2/6 + (a^2*x^2)/4 + (2*a*b*x)/5)/x^6

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sympy [A]  time = 0.22, size = 26, normalized size = 0.87 \[ \frac {- 15 a^{2} x^{2} - 24 a b x - 10 b^{2}}{60 x^{6}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b/x)**2/x**5,x)

[Out]

(-15*a**2*x**2 - 24*a*b*x - 10*b**2)/(60*x**6)

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